00:01
Okay, so we want to solve this equation.
00:02
First, we need to cancel out all the denominators.
00:06
Okay, so we multiply the product of the product of all the denominator, so we can cancel them out.
00:17
So we want to multiply 5 -day minus 11 times 2 -3 times 5 minus -d.
00:27
Okay, so the next step, okay, we multiplied the left or right side by this thing and we we have five times 2 z minus 3 times 5 minus d plus 4 times 5 they minus 11 times 5 minus z then for the right side the left is minus 3 times 5 they minus 11 times 2 day okay, so now we simplify this thing, okay.
01:14
So 10 -day minus 15 times 5 minus z plus 20 -z minus -3 minus -3 minus -3 minus -3 equals to minus -3 plus -3 -1 -4 times 5 minus z equals to minus 15 plus 33, minus 15 z plus 33 times 2 z minus 3.
02:01
So now we further simplify this thing.
02:07
15 minus 75 minus 10 z minus 10 z squared plus 15 d plus 100 z minus 200 z minus 220 minus 20 z squared plus 44 z equals to minus 30 z squared plus 36 z plus 45 z minus 99 okay so first we combine the term with the same the with us squared so minus 10 z squared, minus 20 z squared, okay, minus 30 z squared, and then 50 z, okay, i return with a z, 15 z plus 100 z, 44 z, okay.
03:28
So we have 65, 165, 109 z, right...