Question
Solve each equation on the interval $0 \leq \theta<2 \pi$.$$\sec ^{2} \theta+\tan \theta=0$$
Step 1
We know that $\sec ^{2} \theta = 1 + \tan^2 \theta$, so we can substitute this into the equation to get: \[1 + \tan^2 \theta + \tan \theta = 0\] Show more…
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