0:00
Hello.
00:01
So here we have the equation, p squared minus 4p is equal to 4p times the quantity p minus 1, then minus 3p squared plus 2.
00:09
So we want to first go ahead and remove the parentheses by just using the distributive property.
00:15
So we get a p squared minus 4p and that's going to be then equal to a 4p squared and then a minus 4p, the 4p distributes, and then we have a minus 3 p squared plus.
00:30
2.
00:31
So combining like terms here, while the left hand side, we have a p squared minus 4p, and that's going to be equal to, while 4p squared minus 3p squared, 3p squared is just a 1 p squared.
00:44
So we have a p squared, and then we have the minus 4p plus 2.
00:51
Okay, so then we can go and we can set this equal to 0 by just adding 4p to both sides and then subtracting p squared.
01:01
So then, right, if we do that, subtract p squared.
01:05
So they're gone...