00:01
According to the equation we have been given a quadratic equation 6xx squared equals 2x plus 1 and we have to solve this using the quadratic formula method so what we have to do is that first we have to shift this terms in the right -hand side to the left -hand side so that we can write it in the form of the standard standard form of a quadratic equation so our equation will become 6 xx square minus of 2x minus 1 equals 0 now if we compare this equation with the standard form of a quadratic equation which is a xxxx2 plus equal 0 then the value of a will be equal 6, the value of b will be equals minus of 2, and the value of c will be equals minus of 1.
00:38
Now we know that the solutions of a quadratic equation which has been written in the standard form can be obtained by using the formula minus of b plus minus of square root of b square minus of 4 a c upon 2a.
00:53
Now since we have the values of a, b and c, so we can simply substitute the values in the given formula and obtain our required answers.
00:59
So, minus of b is minus of minus 2, and then we have plus minus of square root of b squared, that is minus of 2 whole square, which is 4, then minus of 4 multiplied by a, which is minus of 1, and then we have 2 a, so 2 multiplied by 6 which is 12.
01:18
So x equals minus of minus 2, which is plus 2, plus minus of square root of 4, minus of 4 multiplied by 6 is minus of 24, and minus of 24 multiplied by minus of 1...