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From here z to the power 64 equal 64 aeta so we have to find 6 root of 64 iata so r equal 64 and 10 theta is not defined so theta equal pi by 2 so 64 iata equals 64 e to the power aita pi by 2 so 6th root of 64 iata 1, 2, 3, 4, 5, 6, equal 6 root of 64 e to the power aita, pi by 2 by 6 plus 2k pi by 6, equal 2 e to the power aita, 5 by 2 ,000, and k5 ,000, and k equal 0, 1, 2, 2 ,000 ,000, 5, 5 by 3, and k equal 0, 1, 2, 3, 2, 3 ,000, 3...