00:01
Question 30 asks for the following equation to be solved, sorry, the following inequality to be solved.
00:09
So to start, i'm going to factor this equation, which will result in 2k minus 8, sorry, 2k plus 8 times k minus 1⁄2.
00:24
It's greater than 0.
00:27
So now i'm going to split this up into two different equations, which will leave us with 2k plus 8.
00:34
And we have to switch the inequality sign, the opposite direction, to, and also we have k minus one half.
00:53
So to start, i'm going to solve the equation on the right, so i'm going to subtract 8 from both sides, and that will leave us with 2k is less than negative 8, and i'm going to divide by 2 on both sides to get k by itself, which will leave us with k is less than negative 4 and then i'm going to solve the right hand with the equation which will start by adding 1 half which will result in k is greater than 1 half so now i'm going to combine these two inequalities into an interval and to do this i'm going to look at both of these equations so we know that k can be any value less than negative 4 so that means that that can start at negative infinity and go all the way to negative 4.
01:57
And because k will never equal negative infinity, it will have a rounded bracket.
02:02
And also, this inequality says that k will never equal 4, so it will also have a rounded bracket.
02:10
So we also know that k can be defined by this equation...