Solve each inequality. Then graph the solution on a number line.
$$2 a-3 \geq 9$$
$a \geq 6$
So we have an equation of to a r Should se an inequality of to a monastery greater than or equal to nine. To solve that, we're gonna add three to both sides, and then we're gonna divide both sides by two. And so we know that a is greater than or equal to six on a number line. We're going to start where six is greater than or equal means that we have a filled in circle and it were greater than we're going to the right. And so there's our solution and our number one.