0:00
All right, welcome back.
00:01
So for this problem, we have 2 divided by x minus 3.
00:09
We'll find our first kind of important value here.
00:13
I want to find out when this denominator is equal to 0.
00:17
So x minus 3 is equal to 0.
00:22
Adding 3 to both sides, we find that that's when x is equal to 3.
00:26
All right.
00:27
Let's now search for other important values here.
00:32
So if we start off with our equation, multiply both sides by x minus 3.
00:37
And we'll give us that.
00:41
Oops, x minus 3.
00:49
There we go.
00:50
We're going to subtract x from both sides, and that gives us 2 is less than negative 3.
00:55
And that is 100 % false.
00:58
So that basically means that, well, this is our only important value for this equation.
01:06
This is the only time when it switches from being greater than 1 to being less than 1.
01:13
So here's our number line here is 1...