00:01
In this question, we're given the 2s square minus 5 s greater equal to the 3.
00:06
The first time we will bring the 3 to the left -hand side, again the 2 -s -square minus 5, s minus 3, greater equal to 0.
00:15
And now let me try to draw, let me call this one with the function f -s here, and if we try to draw the graph here, it will be because a here is equal to 2, and it is positive, therefore we expect to again the open up parabola like this.
00:34
To find the 2x intercept, we need to serve the s1, s2, by the quadratic formula, minus b plus and minus square, root of the p square, minus 4 is c over 2a.
00:48
Then we get equal to the 5 plus and minus.
00:51
Here we have the 25 plus 24, and then divided by 2a...