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Solve each problem by using a system of three equations inthree unknowns.
Three coins. Nelson paid 1.75 dollars for his lunch with13 coins, consisting of nickels, dimes, and quarters. If the number of dimes was twice the number of nickels, then how many of each type of coin did he use?
3 nickels, 6 dimes, 4 quarters
Algebra
Algebra 2
Chapter 4
Systems of Linear Equations
Section 3
Systems of Linear Equations in Three Variables
Polynomials
Systems of Equations and Inequalities
Introduction to Algebra
Graph Linear Functions
Write Linear Equations
Linear Equations and Functions
Matrices and Determinants
Johns Hopkins University
University of California, Berkeley
Lectures
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In the following exercises…
So this is a money question. We know that this person has dimes, Nichols quarters, and in total, he is 13 coins. So then we're told that the total value of the coins, which just point 10 times D those porno five comes and because 0.25 times q equals 1 75 Finally, we're told the number of times it was two times the number of vehicles. So now we have to, um, you substitution here and solved. We can plug in to end for D here, so it's gonna be three. And what's Q equals 13 between q equals 13 minus three. And now we have every variable in terms of the end. So complected into our final equation to salt 0.1 comes to an end plus point of five and close 50.25 irking minus three and 1 75 So now we're gonna have a point to and five and plus 0.25 times 13 3 25 by this point in five times three minus 30.75 and 1 75 So now you 0.25 minus 0.75 So we have my point black and equals 1 75 minus 3 20 minus 1.5. And it's gonna equal three. Once we solve for n equals three, we can solve quickly or d he's gonna equal six. Q is gonna be 13 minus three comes three be four. So we know the number of guys nickels and quarters gonna equal six. Three for we can plug this back, then to make sure, um, that this solution works.
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