Question
Solve each problem.Diagonals of a Parallelogram The sides of a parallelogram are $4.0 \mathrm{cm}$ and $6.0 \mathrm{cm} .$ One angle is $58^{\circ},$ while another is $122^{\circ} .$ Find the lengths of the diagonals of the parallelogram.
Step 1
The law of cosines states that for any triangle with sides of lengths a, b, and c, and an angle γ opposite side c, the following equation holds: \[c^2 = a^2 + b^2 - 2ab \cos(\gamma)\] Show more…
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Solve each problem. The sides of a parallelogram are 4.0 centimeters and 6.0 centimeters. One angle is $58^{\circ}$ and another is $122^{\circ} .$ Find the lengths of the diagonals of the parallelogram.
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Solve each problem. See Examples $1-4$ The sides of a parallelogram are $4.0 \mathrm{cm}$ and $6.0 \mathrm{cm}$. One angle is $58^{\circ}$ while another is $122^{\circ} .$ Find the lengths of the diagonals of the parallelogram.
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Solve each problem. See Examples $1-4$. The sides of a parallelogram are $4.0 \mathrm{cm}$ and $6.0 \mathrm{cm} .$ One angle is $58^{\circ},$ while another is $122^{\circ} .$ Find the lengths of the diagonals of the parallelogram.
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