00:02
Okay, we have this problem about the depth of the water and the flow of the water, and we have two ordered pairs, and we can use those to find the equation of the line, starting with finding the slope.
00:13
So y2 minus y1 would be 1230 minus 826 over x2 minus x2 minus x1, 9 .14 minus 7 .84.
00:24
And that gives us 404 over 1 .3, and if you round that to the nearest hundredth, you get approximately 310 .77.
00:34
Now we can use that and one of our points, i'll go ahead and use the first point to find the equation of the line, starting with point slope form.
00:43
We have y -minus 826 equals 310 .77 times x minus 7 .84.
00:51
So we can simplify that equation.
00:53
We have y minus 826 equals 310 .77x minus 2 ,436 .44 .4 .4.
01:03
Now if you're using an unrounded number for your slope there, you're going to have a slightly different value.
01:10
And then we're going to next add 826 to both sides, and we get y equals 310 .77x minus 1610 .44...