00:01
This problem asks us to look at the national advertising revenue for newspapers, both in the years 2006 and in 2012, and then estimate what we would have in the year 2009 based on those two numbers.
00:18
So starting off in 2006, we had 7 ,505 for our number, and in 2012, 3 ,335.
00:27
And this is in millions of dollars here.
00:30
So to estimate what we may have in between, we can use our midpoint formula, just as we have done by looking at graphs.
00:39
So to do this midpoint formula, we will use x as our time, since that is on the x axis here.
00:46
So x1 here, we'll do m equals x1 would be 2006, and x2 would be 2012.
00:57
So x1 plus x2, divided by 2.
01:01
And then our y coordinates would be the actual revenue in millions of dollars once again so y1 here would be 7 ,505 and y2 would be 3 ,335 divided by 2 so then solving this our x1 plus x2 divided by 2 that gives us the year 2009 which is exactly what we want here.
01:34
So we have 2009 and then taking our y1 plus y2 divided by two, our answer is 5 ,420...