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Solve each quadratic equation by factoring or by …

00:32

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54

Problem 51 Easy Difficulty

Solve each quadratic equation by factoring or by completing the square. See Sections 11.1
and 11.2.
$$
x^{2}+3 x-4=0
$$

Answer

$\{-4,1\}$

Related Courses

Precalculus

Algebra

Beginning and Intermediate Algebra

Chapter 11

Quadratic Equations, Inequalities, and Functions

Section 6

Graphs of Quadratic Functions

Related Topics

Introduction to Conic Sections

Equations and Inequalities

Functions

Polynomials

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Watch More Solved Questions in Chapter 11

Problem 1

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Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 15

Problem 16

Problem 17

Problem 18

Problem 19

Problem 20

Problem 21

Problem 22

Problem 23

Problem 24

Problem 25

Problem 26

Problem 27

Problem 28

Problem 29

Problem 30

Problem 31

Problem 32

Problem 33

Problem 34

Problem 35

Problem 36

Problem 37

Problem 38

Problem 39

Problem 40

Problem 41

Problem 42

Problem 43

Problem 44

Problem 45

Problem 46

Problem 47

Problem 48

Problem 49

Problem 50

Problem 51

Problem 52

Problem 53

Problem 54

Video Transcript

So I'm gonna solve this equation by, um, factoring because I look at these this negative four in this three in the league coefficients one and I can just look for factors of negative for that. Add up the three. So how about four and negative 14 times negative One is negative for four. Plus think of one is three and then we can use the zero product property to say that the solutions must be negative four and positive one.

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Margaret L. Lial , John Hornsby

Beginning and Intermediate Algebra

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Related Topics

Introduction to Conic Sections

Equations and Inequalities

Functions

Polynomials

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