00:01
Alright, we want to solve this quadratic inequality, graph the solution set, and write it in an interval notation.
00:09
So first thing we want to do is move the negative 16 over, so we add 16 to both sides.
00:18
And we need to find what our solution are, so we know that 8 and 2, when you multiply them, they equal 16, and then when you add them, they equal 10, so that works in the inequality so then we know that our solutions are then negative two and negative eight when we graph this since it's an inequality that does not have an equal sign to it they're going to be open circles so there's a negative two and then sorry the negative eight's right there we need to figure out is the inequality going to go within, so is it going to go on the inside of the negative 2 and the negative 8, or is it going to be on the outside of the negative 2 and the negative 8, so that the graph is going to be less than 0.
01:24
So it's going to be on the negative y axis.
01:26
It's going to be on this negative y axis.
01:29
So i just pick a number in between these two to figure out is it going to be in between.
01:36
Between those two solutions.
01:39
So i'm gonna pick negative three, because it's in between negative two and negative eight.
01:43
And i'll just plug that into this equation here.
01:48
So negative three squared plus 10 times negative three, is that less than 16? so negative three squared is nine minus 30, which gives you negative 21, which is indeed less than negative 16.
02:11
So we then know that it's going to actually be in between the negative 2 and negative 8...