Question
Solve each system.$$\begin{aligned}3 a+5 b-3 c &=-4 \\a-3 b+c &=6 \\-4 a+6 b+2 c &=-6\end{aligned}$$
Step 1
Step 1: Multiply the second equation by 3 and add it to the first equation to eliminate $c$: \begin{align*} 3a + 5b - 3c &= -4 \\ 3(a - 3b + c) &= 18 \\ \end{align*} Adding these two equations gives: \begin{align*} 6a - 4b &= 14 \\ \end{align*} Dividing both sides Show more…
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