Question
Solve each system.$$\begin{aligned}&x^{2}+y^{2}=1\\&y=x^{2}+1\end{aligned}$$
Step 1
This gives us: \[x^{2}+(x^{2}+1)^{2}=1\] Simplify this to get: \[x^{4}+2x^{2}+1-1=0\] Which simplifies further to: \[x^{4}+2x^{2}=0\] Show more…
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