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Solve each system by graphing. If a system has no solution or infinitely many solutions, so state. $$\left\{\begin{array}{l}{y=-2 x} \\{2 x+y=-2}\end{array}\right.$$
$-2 x-2-(iii)$
Algebra
Chapter 4
Systems of Linear Equations and Inequalities
Section 1
Solving Systems of Equations by Graphing
Equations and Inequalities
Systems of Equations and Inequalities
Missouri State University
Campbell University
Harvey Mudd College
University of Michigan - Ann Arbor
Lectures
01:32
In mathematics, the absolu…
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Solve each system by graph…
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Without graphing, decide w…
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Graph the solutions of eac…
we've got a system of equations. First equation is why equals two acts negative two acts, and then the second equation is two acts. Plus, why is he quitting? Negative, too. If I look at the first equation, I can see that the M is negative too. I also see that the B is equal to zero because you can rewrite. That is negative. Two x plus zero. That'll be enough for me to Graff that red line here? Zero. And it goes down too. Right? One. Something like that for the blue equation. I'm gonna do X intercept. So zero plus why makes negative too zero negative. Two on why Intercept. Sorry. That's the Y Intercept in the X intercept means why is equal to zero. Two acts equals negative two. So two times, negative one. Okay, so my first point is up is actually sorry. It's down here. Zero common negative, too. And then I have negative one common zero. Again. We got parallel lines. They're not touching each other. And so there's no solution because they're parallel lines.
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