00:01
This problem asks us to solve the system of linear equations given by these two equations, and i want us to do it by graphing.
00:08
And so ultimately we're looking at the graph scene where these two lines are going to intersect.
00:15
So my first step, because this is just the easiest form to graph from, y equals mx plus b, this is slope intercept form.
00:25
The reason why this is so great is that it gives us a y intercept.
00:30
So it gives us our point that's on this up and down y -axis, and then it also gives us a slope.
00:36
So that's our rise overrun.
00:38
That's going to allow us to find other points on the line once we've plotted that y intercept.
00:44
So the first thing that we're going to do here is solve for y in order to get it to this form from both of these equations.
00:52
So for this one, we'll have, let's subtract 2x first.
00:57
We'll get negative 3y equal to negative 2x, plus six, and then we'll need to divide by 3, divide by negative 3.
01:07
So let's do that.
01:12
So when we do that over here, you just get y.
01:16
When we do that over here, we're defining each of these terms by negative 3.
01:20
So negative 2x divided by negative 3 is going to give us 2 thirds, x.
01:28
And then a positive 6 divided by negative 3 will give us a negative 2.
01:32
So we have this equation as 2 thirds x minus 2.
01:41
All right.
01:42
Next down here we'll have subtract 4x and divide by 3.
01:51
This time we'll show this a little bit better.
01:53
We're dividing both terms by 3.
01:55
This gives us y equals negative 4 thirds x plus 4...