00:01
When you're solving a system of equations like this by a substitution, your goal is to either get the x or y by itself in either equation.
00:07
The nice thing is we already have the y by itself right here.
00:12
So it's kind of a nice easy process.
00:14
We can just take that y value and substitute in for y on the other equation.
00:18
So let's do that.
00:20
So the step one here, we don't have to do it.
00:22
We already know that y is equal to negative 3x minus 20.
00:26
So now we're just going to take that value of y and replace it in the other equation.
00:30
Step two.
00:31
So then you get 6 times x plus 2 times the quantity of y, whatever y is, in this case why happens to be negative 3x minus 20, must be equal to 5.
00:48
And now we're going to solve the equation for x.
00:50
So we get 6x plus the quantity of 2 times negative 3x is negative 6x, and 2 times a negative 20 is negative 40, which is distributing.
01:01
And that's equal to 5.
01:04
And then you want to combine your like terms, 6x plus negative 6x is 0.
01:09
So really, this is a 0 minus 40 equals 5.
01:12
And last time i checked, negative 40 doesn't equal 5.
01:15
That's not true.
01:16
So if the variable goes away and you're left with a false statement, this means there's no solution, right? now, what does no solution mean when we're talking about the solution to a system of equations? what it means is that there's no intersection point.
01:30
There's no x and y value where both of these lines have the same solution.
01:35
So these are lines that never intersect, which means that these must be parallel lines.
01:42
Now parallel lines are lines that have the same slope...