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Solve each system by substitution. If a system has no solution or infinitely many solutions, so state.$$\left\{\begin{array}{l}{b=\frac{2}{3} a} \\{8 a-3 b=3}\end{array}\right.$$
$\left(\frac{1}{2}, \frac{1}{3}\right)$
Algebra
Chapter 4
Systems of Linear Equations and Inequalities
Section 2
Solving Systems of Equations by Substitution
Equations and Inequalities
Systems of Equations and Inequalities
Oregon State University
Harvey Mudd College
Idaho State University
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we got B is two or three a and a A minus three B's three. So is plug in ah B from Equation one into a here and to be Excuse me. So that's rewrite that. So eight a minus three into 2/3 A is equal to three, so we'll get eight a minus two A is three. So in that case, six a is three. So a is 3/6, which is equal to half. Now we know that be is equal to 2/3 A. So be is to over three times half, so that's 1/3.
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