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Solve each system by substitution. If a system has no solution or infinitely many solutions, so state.$$\left\{\begin{array}{l}{a=\frac{2}{3} b} \\{9 a+4 b=5}\end{array}\right.$$
$a=\frac{1}{3}$$b=1 / 2$
Algebra
Chapter 4
Systems of Linear Equations and Inequalities
Section 2
Solving Systems of Equations by Substitution
Equations and Inequalities
Systems of Equations and Inequalities
Campbell University
McMaster University
University of Michigan - Ann Arbor
Idaho State University
Lectures
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A is to over three b 98 plus four b is five. All right, so let's put the A substitute A and equation wanted to equation to so nine times to over three b plus four b is five so three and nine cancel. So six B plus four b is five. In that case, 10 b is five. So be is 5/10 which is half we're not done. We need to find a We know that is to over three b So a is to over three. B b is half, so is to over three times half to and to cancel, so a is 1/3.
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