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Solve each system by substitution. If a system has no solution or infinitely many solutions, so state.$$\left\{\begin{array}{l}{2 a-3 b=-13} \\{-b=-2 a-7}\end{array}\right.$$
(-2,3)
Algebra
Chapter 4
Systems of Linear Equations and Inequalities
Section 2
Solving Systems of Equations by Substitution
Equations and Inequalities
Systems of Equations and Inequalities
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All right, so we have the following system off equations given. Let's rewrite co number two here and divide everything by negative one. So that'll be D is to a plus seven. That's an easier way to rewrite equation to. Now let's plug that into number one. So I have to a minus three into to a plus seven. That's equal to minus 13. So to a minus six a minus 21 his minus 13. So minus four a minus 21 is minus 13. That's at 21 on both sides. So minus four A is eight now. Divide negative four on both sides. We'll get a is negative two. We know that B is to a plus seven is negative to plug that in here. B is to into minus two plus seven. These minus four plus seven. So be is three
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