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Solve each system by substitution. See Example 4.$$\left\{\begin{array}{l}{5 u+3 v=5} \\{4 u-v=4}\end{array}\right.$$
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Algebra
Chapter 4
Systems of Linear Equations and Inequalities
Section 2
Solving Systems of Equations by Substitution
Equations and Inequalities
Systems of Equations and Inequalities
Harvey Mudd College
Baylor University
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we have five u plus three V s, five and four U plus v is for So let's modify equation to here. That's isolate V on one side so four minus for you is equal to V. So let's plug that in here. So five you plus three into four minus four. You is equal to five. So five U plus 12 minus 12 you there's five so 12 minus seven you is five. So since 12 minus seven, you is five. Let's at seven. You on both sides. I have 12. 12 is five plus seven. You then subtract five on both sides. We'll get seven is seven U. So u is equal to one since you is one. Well, just plugged that into V is four minus for you So v is four minus for you you is one. So it's plugged that in here. So v is four minus four times one, which is four time minus four. So v is zero
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