00:01
The topic of this question is matrix inverses.
00:04
We're going to be using an inverse matrix to find the solution to this system of equations.
00:12
To start off, we want to turn this system of equations into an equation involving the coefficient matrix, the unknown vector, and the right side vector.
00:28
To do this, simply take away the x and y's to get the coefficient matrix, and then add in the unknown vector, with x and y in it.
00:54
That will be our left side, and the right side is just the vector with these two numbers in it.
01:11
Now we want to solve for x and y, and we want to do that by finding the inverse of the coefficient matrix.
01:23
So let's find the inverse matrix of this matrix using this method of the augmented matrix.
01:31
So we want to start with this augmented matrix with the left matrix being the one we want to find the inverse four, and the right being an identity matrix.
01:44
Then we do row transformations until the left side becomes the identity matrix, at which point the right side will become our inverse matrix.
01:57
First, let's multiply both rows by 10, just to be things cleaner.
02:03
Now let's add twice the first row to three times the second row.
02:09
So 2 times 2 plus 3 times 7 will be 25.
02:17
2 times 3 plus 3 times negative 2 is 0.
02:21
That's why we want to have this type of combination to cancel out to the entry in the second row...