Question
Solve each system.$$\left\{\begin{array}{l}{3 x+2 y-3 z=-2} \\{2 x-5 y+2 z=-2} \\{4 x-3 y+4 z=10}\end{array}\right.$$
Step 1
\begin{align*} 5(3x + 2y - 3z) &= 5(-2)\\ 2(2x - 5y + 2z) &= 2(-2)\\ \end{align*} This gives us: \begin{align*} 15x + 10y - 15z &= -10\\ 4x - 10y + 4z &= -4\\ \end{align*} Subtracting the second equation from the first gives us: \begin{align*} (15x + 10y - 15z) - Show more…
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