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Solve each system of equations. $$\begin{aligned}…

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58

Problem 9 Medium Difficulty

Solve each system of equations.
$$\begin{aligned}&x+y+z=10\\&\begin{array}{ll}x-y & =-1 \\x+y & =5\end{array}\end{aligned}$$

Answer

$\{(2,3,5)\}$

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Watch More Solved Questions in Chapter 4

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Problem 9
Problem 10
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Problem 12
Problem 13
Problem 14
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Problem 16
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Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
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Problem 28
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Problem 30
Problem 31
Problem 32
Problem 33
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Problem 39
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Problem 47
Problem 48
Problem 49
Problem 50
Problem 51
Problem 52
Problem 53
Problem 54
Problem 55
Problem 56
Problem 57
Problem 58

Video Transcript

All right. So here's our system of equations that were given experts. WIPO's equals tan X minus y equals negative one x plus y equals five. So first, we're gonna look at thes 2nd 2 equations we have to solve for one of the variables. So we can actually just treat this as a system of two equations with two unknowns, um, and saw for um X y and then we can plug an accident. Why appear to solve for Z? So let's do that. Let's move this. Why over to the other side that's going to give us X equals live minus one. Now it's substitute y minus one into this equation for acts. So we're gonna have y minus one plus fly equals five. This is gonna give us to why minus one equals five. If we believe that 1/2 y equal six wives in equal three. Now we substitute. Why was three back into this equation? We have ACS minus three equals negative one and therefore access to. So now we have acts and why? And we can plug those back and up here to solve for Z Do that over here. We know that It's two plus. Why? Just three z close to see people's can. And now, from with this two and three to the other side of the equation, you're gonna death that Z equals spots. All right. Our answer as an ordered pair gonna have backs. Why? Z equals X. Which is to why she knows three. And see which we knows. Five you can plug back in these acts.

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Algebra for College Students

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