00:01
We're going to solve this system.
00:03
So we have a plus b plus c equals 6.
00:08
2a minus b plus 3c equal 16, and a plus 3b minus 2c equals negative 6.
00:19
So we're going to solve this using substitution.
00:22
So first off we're going to take these two equations and these two equations.
00:30
We're going to use elimination first, and then.
00:33
We're going to substitute.
00:35
So we're going to take those to first two, a plus b plus c equals 6, and 2a minus b plus 3c equal 16.
00:47
So what we want to do is we're going to have one of these coefficients a, b, or c, that are opposites of each other.
00:54
So it actually already has one.
00:56
We don't have to do any multiplying this b.
00:58
So what i'm going to do is just going to add my equations down.
01:02
So that's 3a.
01:04
My b's here cancel each other out.
01:07
I have plus 4c equals 22.
01:12
And i'm going to do the same thing for these other two ones.
01:17
2a minus b plus 3c equals 16.
01:21
And 2 plus 3b minus 2c equals negative 6.
01:27
So in this one i actually have to multiply one of my variables...