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Solve each system of equations by graphing. $$ \l…

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86 Problem 87 Problem 88 Problem 89 Problem 90 Problem 91 Problem 92 Problem 93 Problem 94

Problem 70 Hard Difficulty

Solve each system of equations by graphing.
$$
\left\{\begin{array}{l}
{y=-4} \\
{-2 x-y=8}
\end{array}\right.
$$

Answer

The lines intersect at the point $(-2,-4),$ so that is the solution for the given system.

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Algebra

Elementary and Intermediate Algebra

Chapter 4

Systems of Linear Equations and Inequalities

Section 1

Solving Systems of Equations by Graphing

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Systems of Equations and Inequalities

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Video Transcript

Okay, so we got why equals negative four for our system and then the other part of the system. Negative two x minus Y equals eight. Uh, the top equation is m X plus B. He was no excess zero X minus four. So my slope zero, it's gonna be horizontal. My y intercept his negative for for the blue equation. I like to find the two intercepts, so make X equals zero. Why has to be negative? Eight make y equals zero x has to be negative for because you divide by negative too. Negative times, negative floors. Positive eight. So then I'm gonna draw my graph. 1st 1 has a b of negative for and the 2nd 1 is a b of negative, eh? So red dot That negative for glued on at Ming and eight, the red line is horizontal the blue and also has an X intercept. Negative for like that. So something like this, that's a little hard to tell. I think that the solution is that ah, I mean, to use a black think looks to me like the solution is that negative too negative for And so let's check it with both equations the Y values, negative force or that part the top equation works. Using the bottom equation, I go negative two x minus y, and we want to see if this gives us eight. This is a positive, for this is a positive force that checks out we have.

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Alan S. Tussy, R. David Gustafson

Elementary and Intermediate Algebra

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