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Solve each system of equations by graphing. $$ \l…

02:06

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86 Problem 87 Problem 88 Problem 89 Problem 90 Problem 91 Problem 92 Problem 93 Problem 94

Problem 60 Hard Difficulty

Solve each system of equations by graphing.
$$
\left\{\begin{array}{l}
{y=2 x-4} \\
{y=-5 x+3}
\end{array}\right.
$$

Answer

The lines intersect at the point $(1,-2),$ so that is the solution for the given system.

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Algebra

Elementary and Intermediate Algebra

Chapter 4

Systems of Linear Equations and Inequalities

Section 1

Solving Systems of Equations by Graphing

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Equations and Inequalities

Systems of Equations and Inequalities

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Watch More Solved Questions in Chapter 4

Problem 1

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Problem 94

Video Transcript

So you got your system. Why? It goes to X minus for and the other part why equals negative five X plus three. And from there you can get your AM in your B and me was to be equals negative for M equals negative. Fine, be equal street. And that's enough information to draw a graph. So the red graph down and negative for, well, boo graph up a positive three. The writer guy goes up to and write one. The blue crab goes down five and write one. You can see that the Intersect right there. At that point of intersection decision here is one comma negative, too.

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Alan S. Tussy, R. David Gustafson

Elementary and Intermediate Algebra

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