00:01
For this problem, we have been given a nonlinear system of equations.
00:04
Xy equals one -sixth.
00:06
Y plus x equals 5xy.
00:09
For this problem, we're going to do a substitution.
00:12
I'm going to take the first equation and solve it for x.
00:16
If i divide both sides by y, i get x equals 1 divided by 6y.
00:22
Now let's do a substitution into our second equation.
00:26
I have y plus x, well, x equals 1 over 6y.
00:31
And five times xy.
00:34
Well, i know from the first equation that xy equals one six.
00:39
So i can make that substitution as well.
00:42
So let's just clean this up a little bit and get rid of those parentheses.
00:50
Now, first things first, let's get rid of our denominators.
00:55
If i multiply both sides by 6y, i can remove the denominators.
01:00
And that gives me 6y squared plus 1.
01:04
And on the right hand side, my six is cancel, and i end up with 5y.
01:09
I can set this all equal to 0.
01:11
Move everything to the left hand side, 6y squared minus 5y plus 1 equals 0...