00:01
In order to solve this system of equations, i will be using a combination of substitution and the elimination method.
00:10
I'm first going to start with using substitution.
00:13
So i'm going to rearrange my first equation in order for it to say y equals.
00:22
And i can do that by simply subtracting 2x from both sides.
00:28
So this will read as y equals negative 2x and then minus 4.
00:38
So all i did there was rearrange.
00:41
Next i am going to substitute.
00:44
Everything that y is equal to where y is located in the next equation.
00:50
So let's write this out.
00:52
I'll have negative 2 times negative 2x minus 4, all in parentheses.
01:02
Plus 4 z equals 0.
01:08
Next, i'll use distributive property.
01:11
So that gives me 4x plus 8 plus 4z equals 0.
01:19
And then i'll subtract 8 from both sides, which leaves me with 4x plus 4z equals negative 8.
01:30
Okay, so now that's my first and my second equation combined.
01:35
Now let's take a look at the third equation, which is 3x minus 2z equals negative 11.
01:44
So these two equations right here, i am going to use the elimination method.
01:53
Now, in order to use the elimination method, i need opposite coefficients.
01:57
And if you look at the z's, i already have a positive and a negative.
02:02
So i'm going to work with that, and i'm going to multiply my second equation.
02:07
Equation by two.
02:10
So let's rewrite this off to the side.
02:13
My first equation will stay the same...