00:01
Look at this question is linear equation systems and substitution and elimination.
00:07
For this question, we want to solve this system using either substitution or elimination.
00:15
Since we have three equations, it's probably easier to use elimination, so let's proceed like that.
00:24
Notice that we have a plus 2 in this equation, plus 2x, and a minus 2x in this equation.
00:33
So numbering these equations 1, 2, and 3, let's add the equations 1 and 2, or 1 and 3 to eliminate x.
00:45
1 plus 3 gives us this equation in y and z, and now let's form another equation just in terms of y and z by eliminating x another way.
00:57
Notice that here, if we multiply by 2, we can get 4x, which is the same number of x as here.
01:04
So by subtracting double the first equation from the second, we can eliminate x again...