00:01
This problem deals with working with systems of any equations using either substitution or elimination.
00:09
Now, in order to answer this problem, the very first thing we're going to have to do is determine which method to use.
00:16
Do we want to use substitution or do we want to use elimination? we are going to choose elimination for this problem.
00:25
Now, as we can see, our problem has fractions in it.
00:30
The best thing to do whenever you see fractions is to get rid of your fractions first.
00:37
So we're going to get rid of our fractions by multiplying by the least common denominator.
00:43
Now let's look at our first equation.
00:46
We have a denominator of x here and a denominator of y here.
00:50
So we're going to multiply by xy.
00:55
In the second equation we have a denominator of x here and a denominator of 2y here.
01:01
So we're going to multiply by 2xy.
01:06
So let's look at our new equations.
01:09
So for the top, this x will cancel out with this x, so we're left with 4y.
01:16
This y will cancel out with this y, so we're left with 3x, and 0 times xy is 0.
01:28
Now, for the second equation, this x will cancel out with this x, and 6 times 2 will give us 12...