00:01
In this problem, we are giving a system of equations, and our goal is to solve using kramer's rule if applicable.
00:08
So in order to do this, we first must find the determinant of the 2x2 matrix that will be built out of the coefficients of x and y from the left side of the equation.
00:22
So in order to do that, we must recall that if we have a 2x2 matrix, maybe it's made up of a, b, c, and d, we can find the determinant by focusing on the diagonals.
00:32
The blue diagonal results in a positive and the red diagonal results in a negative.
00:37
So we have the final determinant to be a times d minus b times c.
00:42
So we're going to first build that determinant out of the coefficients of x and y.
00:50
So the x's will go in the first column on the left, the 2 and the 10.
00:54
And then i take the negative 3 and the positive 10 from the y coefficients for the right -hand column.
00:59
And now i focus by multiplying on the diagonals, blue is the 3.
01:03
Positive, red is negative.
01:05
So the determinant of the coefficients is 2 times 10 to give us 20, minus negative 3 times 10 to give us negative 30.
01:13
A double negative, as you know, turns into a positive.
01:17
So now we have determinant is 20 plus 30 to give us 50.
01:21
And i'm going to circle that to hang on to it for our final step, but first we have to move into step two.
01:29
If the determinant had come out to be zero, kramer's rule could not be applied.
01:43
And this would be because either the system is inconsistent or because there's infinitely many solutions.
01:49
However, we did not get there.
01:51
We found the determinant to be not zero.
01:54
In our case, it was 50.
01:56
So now we calculate the determinant of x and the determinant of y by building two more two by two matrices.
02:08
So the first one for the x's focuses on replacing the coefficients of x with the right -hand side of our original equation.
02:17
So those coefficients of x get replaced by negative 1 and 5, while the right side keeps those coefficients of y...