00:01
Solve the system of equations with matrices using row operations.
00:04
So let's get this into an augmented matrix with coefficients.
00:07
1 -1 -1 -3 -2 -1 -3 -2, with the constant 6 -9 -5 -14.
00:15
And let's get this in a reduced row echelon form.
00:17
So row 1, we already have a positive 1, so let's get 0s below it.
00:20
So we take row 2 and subtract 3 times row 1 and put this in row 2.
00:26
This is going to make a new row 2 of 0, negative 5, 4, negative 23.
00:36
Rows 1 and 3 are unchanged.
00:42
Now let's go to 0 in row 3.
00:44
We could say take row 3 and subtract row 1 and put this in row 3.
00:51
So row 1 and 2 unchanged, and our new row 3 is going to be 0, 2, negative...