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Solve each system. See Sections $8.1-8.3$$$\begin{aligned}&4 x-3 y=-10\\&4 x+6 y=8\end{aligned}$$
$\{(-1,2)\} $
Precalculus
Algebra
Chapter 13
Nonlinear Functions, Conic Sections, and Nonlinear Systems
Section 3
The Hyperbola and Functions Defined by Radicals
Introduction to Conic Sections
An Introduction to Geometry
Functions
Systems of Equations and Inequalities
Harvey Mudd College
University of Michigan - Ann Arbor
Idaho State University
Lectures
01:32
In mathematics, the absolu…
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01:21
Solve each system. See Sec…
00:46
Solve each system by the e…
01:29
Solve each system of equat…
01:49
Solve each system by the a…
03:08
Solve each system by elimi…
00:33
Solve each equation for $y…
Solve each system by subst…
01:12
Solve each system.$$\b…
01:05
Solve each system by the s…
01:36
Solve each system. See Exa…
in this problem, I have the system of equations four X minus three y equals negative 10 and I have four X plus six y equals eight. I have four x and four X in both equations. If one of them was negative weaken, we could use the elimination method. Therefore, I'm gonna leave the first equation alone. Four X minus three y equals negative 10. But I'm gonna multiply the second equation by a negative one. Giving me negative for X minus six y equals negative AIDS. Adding a two equations together, the exes will cancel. I will be left with negative nine y equals negative 18. Dividing both sides by negative nine will give me why is equal to chew. Substituting to back into one of the equations four X minus three times two equals negative. 10 I can solve for the X value four x minus six equals negative 10. Adding six to both sides will give me four x equals negative for so actually equal negative one. That means the point of intersection of these two lines will be negative. One shoot
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