00:01
We're given the following system and need to solve it using substitution.
00:05
So we're going to take the first equation and solve our x by subtracting 2y from both sides.
00:10
So we get x is equal to negative 2y minus 2.
00:13
That negative 2y minus 2 is going to replace the x in the first equation or the second equation.
00:19
So the second equation becomes 4 instead of x, it's negative 2y minus 2 equals negative 2y minus 17.
00:28
We go ahead and distribute and we get negative 8y minus 8 is equal to negative 2y minus 17.
00:35
We start moving things over, so we're going to move the 2y over, and we're going to move the 8 over.
00:41
So we can get all the variables on one side and all the constants on the other side.
00:45
So the 8s cancel out, the 2 ys cancel out.
00:49
We're left with negative 6y is equal to negative 9.
00:52
Divide both sides by negative 6, and you get y is equal to positive 3 halves after reducing the fraction.
00:59
So to get the value of x, we take that value and plug it in for y...