Question

Solve Eqs. (9.4.7) and (9.4.8) numerically by imposing the periodicity condition given in Eq. (9.4.9). Plot $T_0$ and $C_0$ as a function of $E_0$ for a dispersion map made using 70 km of the standard fiber with $D=17 \mathrm{ps} /(\mathrm{km}-\mathrm{nm})$ and 10 km of dispersion-compensating fiber with $D=-115 \mathrm{ps} /(\mathrm{km}-\mathrm{nm})$. Use $\gamma=2 \mathrm{~W}^{-1} / \mathrm{km}$ and $\alpha=0.2 \mathrm{~dB} / \mathrm{km}$ for the standard fiber and $\gamma=6 \mathrm{~W}^{-1} / \mathrm{km}$ and $\alpha=0.5 \mathrm{~dB} / \mathrm{km}$ for the other fiber.

   Solve Eqs. (9.4.7) and (9.4.8) numerically by imposing the periodicity condition given in Eq. (9.4.9). Plot $T_0$ and $C_0$ as a function of $E_0$ for a dispersion map made using 70 km of the standard fiber with $D=17 \mathrm{ps} /(\mathrm{km}-\mathrm{nm})$ and 10 km of dispersion-compensating fiber with $D=-115 \mathrm{ps} /(\mathrm{km}-\mathrm{nm})$. Use $\gamma=2 \mathrm{~W}^{-1} / \mathrm{km}$ and $\alpha=0.2 \mathrm{~dB} / \mathrm{km}$ for the standard fiber and $\gamma=6 \mathrm{~W}^{-1} / \mathrm{km}$ and $\alpha=0.5 \mathrm{~dB} / \mathrm{km}$ for the other fiber.
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Fiber-Optic Communication Systems
Fiber-Optic Communication Systems
Govind P. Agrawal 3rd Edition
Chapter 9, Problem 15 ↓

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Step 1

Identify Eqs. (9.4.7) and (9.4.8) from the context, which typically represent the evolution of the pulse parameters \( T_0 \) and \( C_0 \) in a fiber optic system. Ensure you understand the periodicity condition given in Eq. (9.4.9), which will be crucial for the  Show more…

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Solve Eqs. (9.4.7) and (9.4.8) numerically by imposing the periodicity condition given in Eq. (9.4.9). Plot $T_0$ and $C_0$ as a function of $E_0$ for a dispersion map made using 70 km of the standard fiber with $D=17 \mathrm{ps} /(\mathrm{km}-\mathrm{nm})$ and 10 km of dispersion-compensating fiber with $D=-115 \mathrm{ps} /(\mathrm{km}-\mathrm{nm})$. Use $\gamma=2 \mathrm{~W}^{-1} / \mathrm{km}$ and $\alpha=0.2 \mathrm{~dB} / \mathrm{km}$ for the standard fiber and $\gamma=6 \mathrm{~W}^{-1} / \mathrm{km}$ and $\alpha=0.5 \mathrm{~dB} / \mathrm{km}$ for the other fiber.
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