Question
Solve for the electron carrier concentration and current density at the p region for narrow base diode with high recombination at the edges of depletion $\mathrm{n}$ region.
Step 1
First, we need to understand the structure of a narrow base diode. A narrow base diode is a p-n junction diode where the base (n-region) is very thin compared to the diffusion length of the carriers. This means that the recombination of carriers is significant at Show more…
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Consider a GaAs pn junction with doping concentrations $N_{a}=5 \times 10^{16} \mathrm{~cm}^{-3}$ and $N_{d}=10^{16} \mathrm{~cm}^{-3}$. The junction cross-sectional area is $A=10^{-3} \mathrm{~cm}^{2}$ and the applied forward-bias voltage is $V_{a}=1.10 \mathrm{~V}$. Calculate the $(a)$ minority electron diffusion current at the edge of the space charge region, $(b)$ minority hole diffusion current at the edge of the space charge region, and $(c)$ total current in the pn junction diode.
A $\mathrm{p}^{+} \mathrm{n}$ silicon diode is fabricated with a narrow $\mathrm{n}$ region as shown in Figure $8.11$, in which $W_{n}<L_{p}$. Assume the boundary condition of $p_{n}=p_{\text {mo at }} x=x_{n}+W_{n} \cdot(a)$ Derive the expression for the excess hole concentration $\delta p_{n}(x)$ as given by Equation $(8.31) .(b)$ Using the results of part $(a)$, show that the current density in the diode is given by $$ J=\frac{e D_{p} p_{\mathrm{on}}}{L_{p}} \operatorname{coth}\left(\frac{W_{n}}{L_{p}}\right)\left[\exp \left(\frac{e V}{k T}\right)-1\right] $$
The cross-sectional area of a silicon pn junction is $10^{-3} \mathrm{~cm}^{2} .$ The temperature of the diode is $T=300 \mathrm{~K}$, and the doping concentrations are $N_{d}=10^{16} \mathrm{~cm}^{-3}$ and $N_{a}=$ $8 \times 10^{15} \mathrm{~cm}^{-3} .$ Assume minority carrier lifetimes of $\tau_{n 0}=10^{-6} \mathrm{~s}$ and $\tau_{p 0}=10^{-7} \mathrm{~s}$. Calculate the total number of excess electrons in the $\mathrm{p}$ region and the total number of excess holes in the $\mathrm{n}$ region for $(a) V_{a}=0.3 \mathrm{~V},(b) V_{a}=0.4 \mathrm{~V}$, and $(c) V_{a}=0.5 \mathrm{~V}$.
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