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Solve for $x.$$$10^{\log (3 x+4)}=1$$

$$-3 / 7$$

Algebra

Chapter 4

Exponential and Logarithmic Functions

Section 6

Properties of Logarithmic Functions

Harvey Mudd College

University of Michigan - Ann Arbor

Idaho State University

Lectures

01:40

Solve for $x.$$$10^{\l…

00:31

Solve the logarithmic equa…

02:21

Solve exactly.$$(\…

00:21

Solve the following equati…

01:59

#10. Solve the logarithmic…

00:46

Solve each of the equation…

01:12

Solve for Xlog(4x2 10)…

03:48

Solve the equation$$<…

01:42

Solve the equation.$$\…

01:49

All right, so in this problem doing tend to the log of three X plus four. Now I like to I think it's a good habit to write in your implied base when it's not written equals one. Um, this can't be the right value. This must be a seven when I'm looking at the answer. Uh, but the underlying condition, though, is, uh, as you look at this problem, that 10 toe log based 10, they undo each other. So I'm gonna change that problem based off what the answer was. So next plus four, yeah, is equal to one. That's the main thing to get out of this is that the 10 to the log based 10 undoes itself. So now when you subtract four over well, one minus four is negative three. And then it was you solve for extra and viable sides by seven. So that means X must equal negative three sevens. And sorry if I did the wrong problem here, but I saw the answer and thought that maybe there's a typo in the question. So there you go.

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