By comparing the powers of $2$ and $5$, we get $2x+4=10$ and $x+1=3$. Solving these equations, we get $x=3$.
(b) We can rewrite the equation as $e^{2x} - 5e^{x} + 6 = 0$ as $(e^{x})^{2} - 5e^{x} + 6 = 0$. This is a quadratic equation in $e^{x}$, so we can solve
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