Question
Solve for $x$ in.$$8^{2 x-3}=16^{1-4 x}$$
Step 1
Since 8 and 16 can both be expressed as powers of 2, we rewrite 8 as $2^3$ and 16 as $2^4$. The equation becomes: $$(2^3)^{2x-3} = (2^4)^{1-4x}$$ Show more…
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