00:01
In this question we recall about the formula to compute the cosine of the angle between the two vectors.
00:06
Let's say the vector a and b, then we have the a .b, divided by the norm the vector a times the number of vector b.
00:14
And if this one equals to zero, we say that the two vector they are orthogonal.
00:21
Now in this question we're given the two surfaces.
00:24
The first one will be z equal to the x square plus y square, the second one x plus y square, plus 6x equal to the 33 and the point 1 to 5 now the first step i will create a function f i bring the z on the other side so i have the x square plus y square minus z the function g will be i bring here so i have the x plus y plus 6 z minus 33 the next time i will compute the gradient correspondingly so will be the 2x 2 y minus 1 the gradient of the g it will be 116.
01:08
So if i plug in the point, it will equal to 2, 4 minus 1.
01:18
And this one i will call this a vector a.
01:20
For the gradient g, it will stay the same thing.
01:24
116, it will be the vector b...