00:01
Okay, so i have two different sides of the equation.
00:04
To solve this using the intersection of graphing method, how i would do this is i would look at both sides of the equation, we're going to look at x plus four separately and 1 minus 2x separately, and i'm going to create graphs out of each side.
00:18
So the first side is going to be, let's call it y sub 1 equals x plus 4.
00:23
And then the right side, i'm going to call this y sub 2 equals 1 minus 2x.
00:29
And then i'm just going to graph it on my graphing calculator.
00:32
Our example is going to be on desmos.
00:35
And when i graph these two points on desmos, i get the intersection negative 1, 3.
00:40
Now, with the intersection negative 1 ,3, does that mean both points my answer? only one point is my answer? well, since i only have x in my equation, i'm only looking at the x coordinate, which is going to be negative 1.
00:52
So my intersection of graphing method is telling me that x is negative 1.
00:57
Now let's double check this by solving it symbolically...