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This is for problem number 30 of the section 9 .2 in the book introductory algebra for college students.
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First problem, we are given a quadratic equation 2x squared minus x minus 1 equals 0.
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We're told to solve this for x using the complete -square method.
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So our first step for the complete -square method is that we have to have a binomial in the form of x -squared plus bx.
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And right now, we have this constant in the way.
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So we'll add one to both sides to move to an isolate our binomial.
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And we'll be left with 2x squared minus x equals 1.
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Now we need to get rid of this coefficient 2 in front of our x squared.
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So we'll divide everything by 2.
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And we'll get x squared minus 1 1⁄2 equals 1⁄2.
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So now we have our binomial in the form of x squared plus bx.
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We can now find our b over 2 squared and add it to both sides.
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Normally we would just add it to the binomial, but since this is an equation, what you do to one side, you have to do to both.
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So we're looking for b over two squared.
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Our b, in this case, is going to be our coefficient on our x, which is just one -half.
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So we will have one -half over two squared.
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One -half over two will simplify down to 1 over 4 squared, which you can simplify to 1 over 16.
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So now that we have our b over 2 squared, we can plug that into both sides of our equation.
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So on the left, we'll have x squared minus one -half x plus one over 16 equals one -half plus one over 16.
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Now we can simplify...