00:01
In this problem, the first thing we're being asked to do is to solve the equation for x.
00:04
Well, i see if we have a fraction equal to a fraction, so i'm going to go ahead and cross multiply.
00:07
So first, we'll multiply b plus c times x minus a, and then going the other direction, we're going to multiply b minus c times a times x times x.
00:17
So let's go ahead and use the foil method to multiply these out.
00:21
So on the left -hand side, we'll have b -times x, which is b -x, b -t times a, or sorry, b -times -n -negative -a is negative -b -a, c -t times x is positive cx, and c times negative a is negative ca.
00:35
Now, on the right -hand side, b -times x is b -x, b -t -a is positive b -a, negative c -t times x is negative c -x, and negative c -t times a is negative c -a.
00:50
Well, any terms that are the same on the right and left -hand side would get canceled.
00:54
So the b -x would cancel from each side, and the negative c -a would cancel from each side.
00:59
Now, let's get our x terms on the same side.
01:02
To do this, i'll add cx to both sides because then these two terms will cancel.
01:07
And at the same time, i'll move that b -a term to the right -hand side by adding b -a.
01:14
All right.
01:14
Well, on the left -hand side, we have c -x plus c -x, which is 2c -x...