Question
Solve the equation. (See Examples 5-7)$$\frac{4}{x^{2}-2 x-8}-\frac{1}{x^{2}-16}=\frac{2}{x^{2}+6 x+8}$$
Step 1
The equation is given as: $$ \frac{4}{x^{2}-2 x-8}-\frac{1}{x^{2}-16}=\frac{2}{x^{2}+6 x+8} $$ Factoring the denominators, we get: $$ \frac{4}{(x-4)(x+2)}-\frac{1}{(x-4)(x+4)}=\frac{2}{(x+4)(x+2)} $$ Show more…
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