00:02
Okay, we're going to solve this equation, but we're going to use substitution.
00:06
So we're going to let x equal u to the two -thirds.
00:10
So x squared would just be u to the two -thirds squared.
00:15
You take a power to a power, you multiply your exponents.
00:18
So x squared is u to the four -thirds.
00:22
So i get x squared plus 5x equals negative four.
00:27
Now this just looks like a quadratic function that we could, quadratic equation, excuse me, that we could solve.
00:33
So i'm going to get one side equal to 0.
00:39
I'm going to factor this.
00:40
So i'm going to find the numbers that multiply to 4 and add to 5.
00:46
So it would just be 4 and 1.
00:48
So i get x plus 4, x plus 1 equals 0...