00:01
Alright, so to start off this problem, let's go ahead and translate these y terms in r terms.
00:05
So we'll have r squared minus 2r plus 2 equals to 0.
00:11
And i don't see any obvious factoring, so i'm going to use a quadratic formula.
00:16
So i'll have negative b plus or minus the square root of b squared, minus 4 times a times c, all divided by 2 times a.
00:26
We can simplify it down, so we'll have 2 plus or minus the square root of negative 4.
00:32
Divided by 2, or 2 plus or minus 2 i divided by 2, or 1 plus or minus i.
00:42
And so that's our r value in this case, and from that we can actually build our solution.
00:46
So our solution is y equals to c1, cosine of x plus c2 sine of x, all times e to the x.
00:58
And since we have initial value conditions of y of 0, which equals to y of pi, which equals to 1, we can actually go ahead and solve for c1 and c2.
01:08
So let's go ahead and solve from.
01:10
We have 1 equals to, well, cosine of x is 0.
01:15
Or sorry, cosine of 0 is 1.
01:18
So c1...